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+/* POSIX once-only control.
+ Copyright (C) 2019-2024 Free Software Foundation, Inc.
+
+ This file is free software: you can redistribute it and/or modify
+ it under the terms of the GNU Lesser General Public License as
+ published by the Free Software Foundation; either version 2.1 of the
+ License, or (at your option) any later version.
+
+ This file is distributed in the hope that it will be useful,
+ but WITHOUT ANY WARRANTY; without even the implied warranty of
+ MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+ GNU Lesser General Public License for more details.
+
+ You should have received a copy of the GNU Lesser General Public License
+ along with this program. If not, see <https://www.gnu.org/licenses/>. */
+
+/* Written by Bruno Haible <bruno@clisp.org>, 2019. */
+
+#include <config.h>
+
+/* Specification. */
+#include <pthread.h>
+
+#if (defined _WIN32 && ! defined __CYGWIN__) && USE_WINDOWS_THREADS
+# include "windows-once.h"
+#endif
+
+#if (defined _WIN32 && ! defined __CYGWIN__) && USE_WINDOWS_THREADS
+/* Use Windows threads. */
+
+int
+pthread_once (pthread_once_t *once_control, void (*initfunction) (void))
+{
+ glwthread_once (once_control, initfunction);
+ return 0;
+}
+
+#elif HAVE_PTHREAD_H
+/* Provide workarounds for POSIX threads. */
+
+# if defined __CYGWIN__
+
+# include <stdlib.h>
+
+int
+pthread_once (pthread_once_t *once_control, void (*initfunction) (void))
+{
+ /* In this implementation, we reuse the type
+ typedef struct { pthread_mutex_t mutex; int state; } pthread_once_t;
+ #define PTHREAD_ONCE_INIT { PTHREAD_MUTEX_INITIALIZER, 0 }
+ while assigning the following meaning to the state:
+ state = (<number of waiting threads> << 16) + <1 if done>
+ In other words:
+ state = { unsigned int num_threads : 16; unsigned int done : 16; }
+ */
+ struct actual_state
+ {
+ _Atomic unsigned short num_threads;
+ /* done == 0: initial state
+ done == 1: initfunction executed, lock still active
+ done == 2: initfunction executed, lock no longer usable */
+ _Atomic unsigned short done;
+ };
+ struct actual_state *state_p = (struct actual_state *) &once_control->state;
+ /* This test is not necessary. It's only an optimization, to establish
+ a fast path for the common case that the 'done' word is already > 0. */
+ if (state_p->done == 0)
+ {
+ /* Increment num_threads (atomically), to indicate that this thread will
+ possibly take the lock. */
+ state_p->num_threads += 1;
+ /* Test the 'done' word. */
+ if (state_p->done == 0)
+ {
+ /* The 'done' word is still zero. Now take the lock. */
+ pthread_mutex_lock (&once_control->mutex);
+ /* Test the 'done' word again. */
+ if (state_p->done == 0)
+ {
+ /* Execute the initfunction. */
+ (*initfunction) ();
+ /* Set the 'done' word to 1 (atomically). */
+ state_p->done = 1;
+ }
+ /* Now the 'done' word is 1. Release the lock. */
+ pthread_mutex_unlock (&once_control->mutex);
+ }
+ /* Here, done is > 0. */
+ /* Decrement num_threads (atomically). */
+ if ((state_p->num_threads -= 1) == 0)
+ {
+ /* num_threads is now zero, and done is > 0.
+ No other thread will need to use the lock.
+ We can therefore destroy the lock, to free resources. */
+ if (__sync_bool_compare_and_swap (&state_p->done, 1, 2))
+ pthread_mutex_destroy (&once_control->mutex);
+ }
+ }
+ /* Proof of correctness:
+ * num_threads is incremented and then decremented by some threads.
+ Therefore, num_threads always stays >= 0, and is == 0 at the end.
+ * The 'done' word, once > 0, stays > 0 (since it is never assigned 0).
+ * The 'done' word is changed from == 0 to > 0 only while the lock
+ is taken. Therefore, only the first thread that succeeds in taking
+ the lock executes the initfunction and sets the 'done' word to a
+ value > 0; the other threads that take the lock do no side effects
+ between taking and releasing the lock.
+ * The 'done' word does not change any more once it is 2.
+ Therefore, it can be changed from 1 to 2 only once.
+ * pthread_mutex_destroy gets invoked right after 'done' has been changed
+ from 1 to 2. Therefore, pthread_mutex_destroy gets invoked only once.
+ * After a moment where num_threads was 0 and done was > 0, no thread can
+ reach the pthread_mutex_lock invocation. Proof:
+ - At such a moment, no thread is in the code range between
+ state_p->num_threads += 1
+ and
+ state_p->num_threads -= 1
+ - After such a moment, some thread can increment num_threads, but from
+ there they cannot reach the pthread_mutex_lock invocation, because the
+ if (state_p->done == 0)
+ test prevents that.
+ * From this it follows that:
+ - pthread_mutex_destroy cannot be executed while the lock is taken
+ (because pthread_mutex_destroy is only executed after a moment where
+ num_threads was 0 and done was > 0).
+ - Once pthread_mutex_destroy has been executed, the lock is not used any
+ more.
+ */
+ return 0;
+}
+
+# endif
+
+#else
+/* Provide a dummy implementation for single-threaded applications. */
+
+int
+pthread_once (pthread_once_t *once_control, void (*initfunction) (void))
+{
+ if (*once_control == 0)
+ {
+ *once_control = ~ 0;
+ initfunction ();
+ }
+ return 0;
+}
+
+#endif