/* Search character in UTF-8 string. Copyright (C) 1999, 2002, 2006-2007, 2009-2022 Free Software Foundation, Inc. Written by Bruno Haible , 2002. This file is free software. It is dual-licensed under "the GNU LGPLv3+ or the GNU GPLv2+". You can redistribute it and/or modify it under either - the terms of the GNU Lesser General Public License as published by the Free Software Foundation; either version 3, or (at your option) any later version, or - the terms of the GNU General Public License as published by the Free Software Foundation; either version 2, or (at your option) any later version, or - the same dual license "the GNU LGPLv3+ or the GNU GPLv2+". This file is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License and the GNU General Public License for more details. You should have received a copy of the GNU Lesser General Public License and of the GNU General Public License along with this program. If not, see . */ #include /* Specification. */ #include "unistr.h" uint8_t * u8_strrchr (const uint8_t *s, ucs4_t uc) { /* Calling u8_strlen and then searching from the other end would cause more memory accesses. Avoid that, at the cost of a few more comparisons. */ uint8_t *result = NULL; uint8_t c[6]; if (uc < 0x80) { uint8_t c0 = uc; for (;; s++) { if (*s == c0) result = (uint8_t *) s; if (*s == 0) break; } } else switch (u8_uctomb_aux (c, uc, 6)) { case 2: if (*s) { uint8_t c0 = c[0]; uint8_t c1 = c[1]; /* FIXME: Maybe walking the string via u8_mblen is a win? */ for (;; s++) { if (s[1] == 0) break; if (*s == c0 && s[1] == c1) result = (uint8_t *) s; } } break; case 3: if (*s && s[1]) { uint8_t c0 = c[0]; uint8_t c1 = c[1]; uint8_t c2 = c[2]; /* FIXME: Maybe walking the string via u8_mblen is a win? */ for (;; s++) { if (s[2] == 0) break; if (*s == c0 && s[1] == c1 && s[2] == c2) result = (uint8_t *) s; } } break; case 4: if (*s && s[1] && s[2]) { uint8_t c0 = c[0]; uint8_t c1 = c[1]; uint8_t c2 = c[2]; uint8_t c3 = c[3]; /* FIXME: Maybe walking the string via u8_mblen is a win? */ for (;; s++) { if (s[3] == 0) break; if (*s == c0 && s[1] == c1 && s[2] == c2 && s[3] == c3) result = (uint8_t *) s; } } break; } return result; }