blob: 309f3234ebc33c296724a8660815a14adc0ab863 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
|
/* Search character in UTF-8 string.
Copyright (C) 1999, 2002, 2006-2007 Free Software Foundation, Inc.
Written by Bruno Haible <bruno@clisp.org>, 2002.
This program is free software: you can redistribute it and/or modify it
under the terms of the GNU Lesser General Public License as published
by the Free Software Foundation; either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>. */
#include <config.h>
/* Specification. */
#include "unistr.h"
uint8_t *
u8_strrchr (const uint8_t *s, ucs4_t uc)
{
/* Calling u8_strlen and then searching from the other end would cause more
memory accesses. Avoid that, at the cost of a few more comparisons. */
uint8_t *result = NULL;
uint8_t c[6];
if (uc < 0x80)
{
uint8_t c0 = uc;
for (;; s++)
{
if (*s == c0)
result = (uint8_t *) s;
if (*s == 0)
break;
}
}
else
switch (u8_uctomb_aux (c, uc, 6))
{
case 2:
if (*s)
{
uint8_t c0 = c[0];
uint8_t c1 = c[1];
/* FIXME: Maybe walking the string via u8_mblen is a win? */
for (;; s++)
{
if (s[1] == 0)
break;
if (*s == c0 && s[1] == c1)
result = (uint8_t *) s;
}
}
break;
case 3:
if (*s && s[1])
{
uint8_t c0 = c[0];
uint8_t c1 = c[1];
uint8_t c2 = c[2];
/* FIXME: Maybe walking the string via u8_mblen is a win? */
for (;; s++)
{
if (s[2] == 0)
break;
if (*s == c0 && s[1] == c1 && s[2] == c2)
result = (uint8_t *) s;
}
}
break;
case 4:
if (*s && s[1] && s[2])
{
uint8_t c0 = c[0];
uint8_t c1 = c[1];
uint8_t c2 = c[2];
uint8_t c3 = c[3];
/* FIXME: Maybe walking the string via u8_mblen is a win? */
for (;; s++)
{
if (s[3] == 0)
break;
if (*s == c0 && s[1] == c1 && s[2] == c2 && s[3] == c3)
result = (uint8_t *) s;
}
}
break;
}
return result;
}
|